Optimal. Leaf size=167 \[ \frac{16 i a^2}{45 d e^4 \sqrt{a+i a \tan (c+d x)} \sqrt{e \sec (c+d x)}}-\frac{32 i a \sqrt{a+i a \tan (c+d x)}}{45 d e^4 \sqrt{e \sec (c+d x)}}-\frac{4 i a \sqrt{a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac{2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}} \]
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Rubi [A] time = 0.285546, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.1, Rules used = {3497, 3502, 3488} \[ \frac{16 i a^2}{45 d e^4 \sqrt{a+i a \tan (c+d x)} \sqrt{e \sec (c+d x)}}-\frac{32 i a \sqrt{a+i a \tan (c+d x)}}{45 d e^4 \sqrt{e \sec (c+d x)}}-\frac{4 i a \sqrt{a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac{2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}} \]
Antiderivative was successfully verified.
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Rule 3497
Rule 3502
Rule 3488
Rubi steps
\begin{align*} \int \frac{(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx &=-\frac{2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}+\frac{(2 a) \int \frac{\sqrt{a+i a \tan (c+d x)}}{(e \sec (c+d x))^{5/2}} \, dx}{3 e^2}\\ &=-\frac{4 i a \sqrt{a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac{2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}+\frac{\left (8 a^2\right ) \int \frac{1}{\sqrt{e \sec (c+d x)} \sqrt{a+i a \tan (c+d x)}} \, dx}{15 e^4}\\ &=\frac{16 i a^2}{45 d e^4 \sqrt{e \sec (c+d x)} \sqrt{a+i a \tan (c+d x)}}-\frac{4 i a \sqrt{a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac{2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}+\frac{(16 a) \int \frac{\sqrt{a+i a \tan (c+d x)}}{\sqrt{e \sec (c+d x)}} \, dx}{45 e^4}\\ &=\frac{16 i a^2}{45 d e^4 \sqrt{e \sec (c+d x)} \sqrt{a+i a \tan (c+d x)}}-\frac{4 i a \sqrt{a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac{32 i a \sqrt{a+i a \tan (c+d x)}}{45 d e^4 \sqrt{e \sec (c+d x)}}-\frac{2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}\\ \end{align*}
Mathematica [A] time = 0.552318, size = 113, normalized size = 0.68 \[ \frac{a (\cos (d x)-i \sin (d x)) \sqrt{a+i a \tan (c+d x)} (-54 \sin (c+d x)+10 \sin (3 (c+d x))-81 i \cos (c+d x)+5 i \cos (3 (c+d x))) (\cos (c+2 d x)+i \sin (c+2 d x))}{90 d e^4 \sqrt{e \sec (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.372, size = 113, normalized size = 0.7 \begin{align*} -{\frac{2\,a \left ( 5\,i \left ( \cos \left ( dx+c \right ) \right ) ^{4}-5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) -2\,i \left ( \cos \left ( dx+c \right ) \right ) ^{2}-8\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +16\,i \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{45\,d{e}^{9}}\sqrt{{\frac{a \left ( i\sin \left ( dx+c \right ) +\cos \left ( dx+c \right ) \right ) }{\cos \left ( dx+c \right ) }}} \left ({\frac{e}{\cos \left ( dx+c \right ) }} \right ) ^{{\frac{9}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.949, size = 216, normalized size = 1.29 \begin{align*} \frac{{\left (-5 i \, a \cos \left (\frac{9}{2} \, d x + \frac{9}{2} \, c\right ) + 15 i \, a \cos \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ) - 27 i \, a \cos \left (\frac{5}{3} \, \arctan \left (\sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ), \cos \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right )\right )\right ) - 135 i \, a \cos \left (\frac{1}{3} \, \arctan \left (\sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ), \cos \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right )\right )\right ) + 5 \, a \sin \left (\frac{9}{2} \, d x + \frac{9}{2} \, c\right ) + 15 \, a \sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ) + 27 \, a \sin \left (\frac{5}{3} \, \arctan \left (\sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ), \cos \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right )\right )\right ) + 135 \, a \sin \left (\frac{1}{3} \, \arctan \left (\sin \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right ), \cos \left (\frac{3}{2} \, d x + \frac{3}{2} \, c\right )\right )\right )\right )} \sqrt{a}}{180 \, d e^{\frac{9}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.16664, size = 317, normalized size = 1.9 \begin{align*} \frac{{\left (-5 i \, a e^{\left (8 i \, d x + 8 i \, c\right )} - 32 i \, a e^{\left (6 i \, d x + 6 i \, c\right )} - 162 i \, a e^{\left (4 i \, d x + 4 i \, c\right )} - 120 i \, a e^{\left (2 i \, d x + 2 i \, c\right )} + 15 i \, a\right )} \sqrt{\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt{\frac{e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (-\frac{3}{2} i \, d x - \frac{3}{2} i \, c\right )}}{180 \, d e^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}{\left (e \sec \left (d x + c\right )\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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